清华大学材料力学45章习题答案
第 3 章Es As F = Ns E A + E A FP s s a a E a Aa F = FP Na Es As + E a Aa (1).复合材料柱横截面上正应力与FP、b0、b1、h和Ea、Es之间的关系式 FNa Ea FP σa = = Aa b0 hEs + 2b1hEaσs = FNs E s FP E s FP = = As E s b0 h + E a 2b1 h b0 hE s + 2b1 hE a(2). 已知FP = 385kN;Ea = 70GPa,Es = 200GPa;b0 = 30mm,b1 = 20mm, h = 50mm。求铝板与钢板横截面上的最大正应力。

