C++求矩阵的逆程序代码
b[ip] = b[i];
if (ii>=0)
for (j=ii;j<i;j++) sum -= a[i][j] * b[j]; else if (sum) ii = i;
b[i] = sum;
}
for (i=n-1;i>=0;i--)
{
sum = b[i];
for (j=i+1;j<n;j++) sum -= a[i][j] * b[j]; b[i] = sum / a[i][i];
}
}
C++求矩阵的逆程序代码
b[ip] = b[i];
if (ii>=0)
for (j=ii;j<i;j++) sum -= a[i][j] * b[j]; else if (sum) ii = i;
b[i] = sum;
}
for (i=n-1;i>=0;i--)
{
sum = b[i];
for (j=i+1;j<n;j++) sum -= a[i][j] * b[j]; b[i] = sum / a[i][i];
}
}
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