杭电复习资料1“发电厂电气部分”复习资料

G115kVT6.3kVRlWk(3)0.2?/kml?50km30MVAU%?10.5k6.3kV0.3kAX%?4r0.05?/kml?1.0km

解：IB?SB100S100??9.164,X1?x1lB?0.2*50*?0.0756， 22UB11153UB3*6.32uk%UNSB10.5100?*?0.35,?UB?Uav,XT?2100UBSN10030XR?xl%ULNIB46.39.164?**?1.222

100ILNUB1000.36.3SB100?0.05*1*?0.126 2UB6.32XW?x2lX?*?X1?XT?XR?XW=0.0756+0.35+1.222+0.126=1.7736

I*''?11??0.5638 X*1.7736?I''?I*''*IB?0.5638*9.164?5.167(kA)

iM?2KMI''?2.55I''?2.55*5.167?13.176(kA) sK?S?SB?I*''U*SB?0.5638*100?56.38(MVA)

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