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CO2＋NaOH === NaHCO3
因NaHCO3溶液和Na2CO3溶液均呈碱性，则溶液中的溶质可能是Na2CO3或NaHCO3.
(2)由AB段产生气体可知发生反应的离子方程式为：HCO ＋H＋ === CO2↑＋H2O，此段消耗的n(H＋)＝1 mol/L ×0.1 L＝0.1 mol，故溶液中n(CO )＝n(HCO )＝0.1 mol. ①OA段CO 消耗0.1 mol H＋，OH－消耗0.1 mol H＋. ③ V(CO2)＝0.1 mol×22.4 L/mol＝2.24 L 答案：(1)Na2CO3或NaHCO3
(2)①H＋＋OH－ === H2O；CO ＋H＋ === HCO ②2240